Question

Me ajudem a calcular o valor das potências

Answer 1

Resposta:

ver abaixo

Explicação passo-a-passo:

$d)(\frac{5}{4})^{-3}=(\frac{4}{5})^{3}=\frac{125}{64}\\\\e)(-\frac{2}{3})^{-2}=(\frac{3}{2})^{2}=\frac{9}{4}\\\\f)(\frac{1}{10})^{-2}=10^{2}=100\\\\g)4^{-2}=(\frac{1}{4})^{2}=\frac{1}{16}\\\\h)(-3)^{-2}=(-\frac{1}{3})^{2}=\frac{1}{9}\\\\i)(\frac{1}{5})^{-3}=5^{3}=125\\\\j)(-\frac{1}{4})^{-3}=(-4)^{3}=-64\\\\k)(\frac{5}{10})^{-1}=\frac{10}{5}=2\\\\l)6^{-3}=(\frac{1}{6})^3=\frac{1}{216}$