Question

me ajudem!!
a) 13+4(2x-1=5(x+2)
b) 2-4x=32-18x+12

Answer 1

$Resolu\c{c}\~ao(a) \to \left\{\begin{array}{ccc}13+4*(2x-1) = 5*(x+2)\\\\13+8x-4 = 5x+10\\\\8x-5x = 10-13+4\\\\3x = 1\\\\ \boxed{x = \frac{1}{3}} \end{array}\right$

$Resolu\c{c}\~ao(b) \to \left\{\begin{array}{ccc}2-4x = 32-18x+12\\\\-4x+18x = 32+12-2\\\\14x = 42\\\\ \boxed{x = \frac{42}{14} = 3} \end{array}\right$

Espero ter ajudado. :))

Answer 2

   

a) 13+4(2x-1=5(x+2)
      13+8x - 4 = 5x + 10
           8x - 5x =10 - 9
                3x = 1
                  x = 1/3

b) 2-4x=32-18x+12
      -4x+18x = 12+32-2
            14x = 42
              x = 3