Question

me ajudem
2x²-8x+8=0
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Answer 1

Resposta:

2x²-8x=0-8

4x-8x=0-8

-4x=-8(-1)

x= 8/4

x= 2

Answer 2

Resposta:

2x^2 - 8x + 8= 0 ( simplifica por dois)

x^2 - 4x + 4=0

∆= b^2 - 4ac

∆= (-4)^2 - 4. 1 .4

∆= 16 - 16

∆= 0

x= -b +/- √∆

2a

x= -(-4) +/- 0

2a

x= 4 +/- 0

2

xI= 4/2 = 2

xII= 4/2 = 2

S= {2}