Question

Me ajudem 2n sobre 3+n=1-0,6

Answer 1

$\dfrac{2n}{3+n}=1-0,6$

$\dfrac{2n}{3+n}=0,4$

$2n=(3+n)\cdot0,4$

$2n=1,2+0,4n$

$2n-0,4n=1,2$

$1,6n=1,2$

$n=\dfrac{1,2}{1,6}$

$n=\dfrac{12}{16}$

$n=\dfrac{3}{4}$

Answer 2

2n/3+n = 1-0,6
2n/3+n = 0,4
2n = 0,4(3+n)
2n = 1,5 + 0,4n
2n - 0,4n = 1,5
1,6n = 1,5
n = 1,5/1,6
n = 0,75