Question

me ajudem : (21x^5yz²+14xyz):(3xyz²)=
6m^4 x(4m³-3m)=

Answer 1

a) $\dfrac{21x^{5}yz^2+14xyz}{3xyz^{2}}$

$=\dfrac{7 \cdot xyz\cdot \left(3x^{4}z+2 \right )}{3\cdot xyz \cdot z}\\ \\ =\dfrac{7\cdot \left(3x^{4}z+2\right )}{3z}\\ \\ \\ \boxed{\dfrac{21x^{5}yz^2+14xyz}{3xyz^{2}}=\dfrac{7\cdot \left(3x^{4}z+2\right )}{3z}}$


b) $6m^{4} \cdot \left(4m^{3}-3m\right)$

$6m^{4} \cdot \left(4m^{3}-3m\right)\\ \\ =6\cdot 4 \cdot m^{4+3}-6 \cdot 3 \cdot m^{4+1}\\ \\ =\boxed{24m^{7}-18m^{5}}$