Question

Me ajudem 2(x² -7 x + 12) = 1

Answer 1

espero ter ajudado o meu resultado deu isso

Answer 2

Resposta:

S={(7-√3)/2, (7+√3)/2}

Explicação passo-a-passo:

2(x² -7 x + 12) = 1

2x² -14 x + 24 = 1

2x² -14 x + 24 - 1=0

2x² -14 x + 23=0

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~2x^{2}-14x+23=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=2{;}~b=-14~e~c=23\\\\\Delta=(b)^{2}-4(a)(c)=(-14)^{2}-4(2)(23)=196-(184)=12\\\sqrt{\Delta}=\sqrt{12}=\sqrt{4.3}= \sqrt{4}.\sqrt{3}=2\sqrt{3} \\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(-14)-2\sqrt{3}}{2(2)}=\frac{14-2\sqrt{3}}{4}=\frac{7-\sqrt{3}}{2}\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(-14)+2\sqrt{3}}{2(2)}=\frac{14+2\sqrt{3}}{4}=\frac{7+\sqrt{3}}{2}$