Question

ME AJUDEM, 2 PERGUNTAS SÓ

-b+√b²-4ac/ 2a para a = -1 e b= 5 c= 6

Answer 1

-b+\/b^2-4ac/2a=>

-5+\/5^2-4 (-1)*6/2*(-1)

-5+\/25 + 24 / -2

-5+5+24/ -2

24/-2

-12

Answer 2

delta = b² - 4(a)(c)
delta = 25 -4(-1)(6)
delta = 25 + 24
delta = 49

x1 = -b + √delta/2a
x1 = -5 + 7 / -2
x1 = -1

x2 = -b - √delta/2a
x2 = -5 -7/-2
x2 = 6