Matemática, perguntado por Yunokawwaii, 6 meses atrás

me ajudem 2х²- 7х+3=0​

Soluções para a tarefa

Respondido por attard
2

\Large\mathsf\displaystyle{} {2x}^{2}  - 7x + 3 = 0 \\\\ \Large\mathsf\displaystyle{}\begin{cases}a = 2 \\ b =  - 7 \\ c = 3\end{cases} \\\\ \Large\mathsf\displaystyle{}x =  \dfrac{ -\left( - 7\right) \pm \sqrt{\left( - 7\right)^{2} - 4\cdot2 \cdot3}  }{2\cdot2}   \\ \\\\\Large\mathsf\displaystyle{}x =   \dfrac{7 \pm \sqrt{49 - 24} }{4} \\\\  \Large\mathsf\displaystyle{}x =  \dfrac{7 \pm \sqrt{25} }{4}  \\\\ \\  \Large\mathsf\displaystyle{}x =  \dfrac{7 \pm5}{4}  \\\\ \\  \Large\mathsf\displaystyle{}x =  \dfrac{7 + 5}{4}  \\\\ \\  \Large\mathsf\displaystyle{}x =  \dfrac{7 - 5}{4} \\  \\ \\  \Large\mathsf\displaystyle{}x =  3  \\ \\\Large\mathsf\displaystyle{}x =  \dfrac{1}{2}   \\  \\

\Large\displaystyle\text{$\begin{gathered} \underline{\boxed{\boldsymbol{  x_{1} =  \dfrac{1}{2}   \: ou \:  \: 0,5  }}}\end{gathered}$}

\Large\displaystyle\text{$\begin{gathered} \underline{\boxed{\boldsymbol{   x_{2} = 3 \\  }}}\end{gathered}$}

\Large\mathsf\displaystyle{}\displaystyle\text{$\begin{gathered} \underline{\boxed{\boldsymbol{{ \red{Bons}}  \blue{\:Estudos}}}}\end{gathered}$}

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