Question

Me ajudem!! 1. Seja f(x) = 2x² - 3x +1.Calcule f(√2/3) .

Answer 1

$f(x) = 2x^{2}-3x+1 \\ f( \sqrt{ \frac{2}{3} } ) = 2(\sqrt{ \frac{2}{3} } )^{2}-3(\sqrt{ \frac{2}{3} } )+1 \\ \\ f( \sqrt{ \frac{2}{3} } ) = \frac{4}{3} - 3\sqrt{ \frac{2}{3} } +1 \\ \\ f( \sqrt{ \frac{2}{3} } ) = \frac{4}{3} - 3\frac{ \sqrt{2} }{ \sqrt{3} } +1 \\ \\ f( \sqrt{ \frac{2}{3} } ) = \frac{4 \sqrt{3}-9 \sqrt{2}+3 \sqrt{3} }{3 \sqrt{3} } \\ \\ f( \sqrt{ \frac{2}{3} } ) = \frac{7 \sqrt{3}-9 \sqrt{2} }{3 \sqrt{3} }$