Question

Me ajudeem, por favor!!​

Answer 1

Resposta:

a)

$f(0) = 0 ^{2} - 5 \times 0 + 6 = 6 \\ f(2) = 2 ^{2} - 5 \times 2 + 6 = 0 \\ f(3) = 3 ^{2} - 5 \times 3 + 6 = 0$

b)

$x ^{2} - 5x + 6 = 0 \\ x = (5 + - \sqrt{25 - 24} ) \div 2 \\ x = (5 + - 1) \div 2 \\ x = 2 \: ou \: x = 3$

c)

$x ^{2} - 5x + 6 = 20 \\ x ^{2} - 5x - 14 = 0 \\ x = (5 + - \sqrt{25 + 56} ) \div 2 \\ x = (5 + - 9) \div 2 \\ x = 14 \: ou \: x = - 2$

Answer 2

A) R:0
B) R:3
C) R: -2