Question

Me ajudeeem ,por favor , a resolver isso, 19 pontos

Answer 1

$Resolu\c{c}\~ao(4)\to \left\{\begin{array}{ccc}Z = \frac{4x+3}{12}-2,\ quando\ Z=-3\\\\-3 = \frac{4x+3}{12}-2\\\\ \frac{4x+3}{12} = -3+2\\\\ \frac{4x+3}{12} = -1\\\\4x+3 = -12\\\\4x = -15\\\\\boxed{x = -\frac{15}{4} } \to Letra\ B \end{array}\right$

$Resolu\c{c}\~ao(5)\to \left\{\begin{array}{ccc}\frac{x}{3}+2x = 3*14\\\\ \frac{x}{3}+2x =42\\\\ \frac{x}{3} = 42-2x\\\\x = 3*(42-2x)\\\\x = 126-6x\\\\7x = 126\\\\\boxed{x = \frac{126}{7} = 18 }\to Letra\ C \end{array}\right$

Espero ter ajudado. :))

Answer 2

a) 4x+3 - 2 = -3
     12
4x + 3 -24 = - 36
      
  4x = - 36 - 21
   
   x = - 57
           4

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b )   x  + 2x = 3.14
           3
    x + 2x  = 42
    3
    x + 6x= 126
       7x = 126
   
         x = 18

===========================================================
   4(3x +7) = 3 + x + 16
    12x + 28 = x + 19
     12x - x = 19-28
           11x = 9
                x = 9/11

Obs> Não tenho certeza pois o exercício estar INCOMPLETO