Question

Me ajude pfvr em expressão algébrica

f) 9.(x+3) -18
g) 6.(x-3)+10x
H)6.(x -15)+3.(x+8)
I)2.(x-4)-x
J) 7.(2.x+4)-3.(x-2)
K) 8.(3x+5)-2.(3x-4)

Answer 1

Explicação passo-a-passo:

f)

$9.(x + 3) - 18 = 0 \\ 9x + 27 - 18 = 0 \\ 9x = 18 - 27 \\ 9x = 9 \\ x = \frac{9}{9} \\ x = 1$

g)

$6.(x - 3) + 10x = 0\\ 6x - 18 + 10x = 0 \\ 16x = 18 \\ x = \frac{18}{16} \\ \\ x= \frac{9} {8}$

h)

$6.(x - 15) + 3.(x + 8) = 0 \\ 6x - 90 + 3x + 24 = 0 \\ 9x = 90 - 24 \\ 9x = 66 \\ x = \frac{66}{9} \\ \\ x = \frac{22}{3}$

i)

$2.(x - 4) - x = 0 \\ 2x - 8 - x = 0 \\ x = 8$

j)

$7.(2x + 4) - 3.(x - 2) = 0 \\ 14x + 28 - 3x + 6 = 0 \\ 11x = - 28 - 6 \\ 11x = - 34 \\ x = \frac{ - 34}{11}$

k)

$8 .(3x + 5) - 2.(3x - 4) = 0 \\ 24x + 40 - 6x + 8 = 0 \\ 18x = - 40 - 8 \\ 18x = - 48 \\ x = \frac{ - 48}{18}$

Bons estudos...

Answer 2

Explicação passo-a-passo:

$f)9 \times (x + 3) - 18 \\ 9(x + 3 - 2) \\9(x + 1) \\ \\ g)6 \times (x - 3) + 10x \\ 2(3(x - 3) + 5x) \\ 2(3x + 9 + 5x) \\ 2(8x - 9)$

$h)6 \times (x - 15) + 3 \times (x + 8) \\ 3(2(x - 15) + x + 8) \\ 3(2x - 30 + x + 8) \\ 3(3x - 22) \\ \\ i)2 \times (x - 4) - x \\ 2x - 8 - x \\ x - 8$

$j)7 \times (2 \times x + 4) - 3 \times (x - 2) \\ 14x + 28 - 3x + 6 \\ 11x + 34 \\ \\ \\ k)8 \times (3x + 5) - 2 \times (3x - 4) \\ 2(4(3x + 5) - (3x - 4)) \\ 2(12x + 20 - 3x + 4) \\ 2(9x + 24) \\ 2 \times 3(3x + 8) \\ 6(3x + 8)$

• Espero ter ajudado.