Question

ME AJUDE É PARA HOJE





a) (4a + 4) · (4a – 4)


b) (b –12) . ( b + 12)


c) (6y² + 7y) . (6y² – 7y)


d) (a²/2 – 5) . (a²/2 + 5)


e) (0,5x + 2) . (0,5x – 2)


f) (x + 3y/2) . (x - 3y/2)

Answer 1

Resposta:

Explicação passo a passo:

a) (4a + 4) · (4a – 4)

= (4a)^2 - 4^2

= 16a^2 - 16

_________________

b) (b –12) . ( b + 12)

= b^2 - 12^2

= b^2 - 144

__________________

c) (6y² + 7y) . (6y² – 7y)

= (6y^2)^2 - (7y)^2

= 36y^4 - 49y^2

__________________

d) (a²/2 – 5) . (a²/2 + 5)

= (a²/2)^2 - 5^2

= a^4 /4 - 25

____________________

e) (0,5x + 2) . (0,5x – 2)

= (0,5x)^2 - 2^2

= 0,25 x^2 - 4

___________________

f) (x + 3y/2) . (x - 3y/2)

= x^2 - (3y/2)^2

= x^2 - 9y^2 / 4