Question

me AJUDE COM A RESPOSTA, por favor ​

Answer 1

V(x,y)=12/√(16+x²+y²)

x=2

y=-4

V(2,-4)=12/√(16+2²+(-4)²)

V(2,-4)=12/√16+4+16

V(2,-4)=12/6

[V(2,-4)=2 volts]

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