Question

Me ajude aqui tbm por obséquio, me ajudaria bastante<3​

Answer 1

Explicação passo a passo:

a)

(1/4)^x = 64

4^-x = 64

4^-x = 4^3

-x = 3

x = -3

b)

5^2x = 625

5^2x = 5^4

2x = 4

x = 2

c) $(\sqrt[6]{2})^x = 0,5\\(\sqrt[6]{2})^x = 1/2\\(\sqrt[6]{2})^x = 2^-1\\2^{x/6} = 2^-1\\x/6 = -1\\x = -6$

Answer 2

Explicação passo a passo:

a)

$({1\over4})^x=64\\ \\ ({1\over4})^x=4^3\\ \\ ({1\over4})^x=({1\over4})^{-3}\\ \\ cancela~~base\\ \\\fbox{ x=-3 }$

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b)

$5^{2x}=625\\ \\\not 5^{2x}=\not5^4\\ \\ 2x=4\\ \\ x={4\over2}\\ \\\fbox{ x=2 }$

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c)

$(\sqrt[6]{2} )^x=0,5\\ \\ \sqrt[6]{2^x} ={5\over10}\\ \\ 2^{x\over6}={1\over2}\\ \\ 2^{x\over6}=2^{-1}\\ \\ {x\over6}=-1\\ \\\fbox{ x=-6 }$