Question

me ajude a fazer a formula de bascara x^2+6^x-112=0

Answer 1

x2+6x-112=0
a= (1) b= (6) c= (-112)
∆= b²-4.a.c
∆= 6²-4.(1).(-112)
∆= 36+448
∆= 484
X= -b+-√∆
. ______
. 2.a

X= -6+-22
. ______
. 2

.......

solução: -14 e 8

Answer 2

$x^2+6x-112=0$

Coeficientes: a = 1, b = 6 e c = -112

$\Delta=b^4-4ac\\\Delta=6^2-4.1.(-112)\\\Delta=36+448\\\Delta=484$

$x=\frac{-b+-\sqrt{\Delta}}{2a}\\\\x=\frac{-6+-\sqrt{484}}{2.1}\\\\x=\frac{-6+-22}{2}\\\\x_1=\frac{-6+22}{2}=\frac{16}{2}=8\\\\x_2=\frac{-6-22}{2}=\frac{-28}{2}=-14$

Espero ter ajudado.
Bons estudos! :)