Question

ME AJUDAAAAAAAAAAAAAA​

Answer 1

primeiro um aviso

0,333...=$\frac{3}{9} =\frac{1}{3}$

então resolvendo

$2-[\frac{1}{2}:4-6^{0}+[5+(2^{2}:0,333...)]]\\\\2-[\frac{1}{2}:4-1+[5+(4:\frac{1}{3})]]\\\\2-[\frac{1}{2}:4-1+[5+12]]\\\\2-[\frac{1}{2}:4-1+17]\\\\2-[8-1+17]\\2-[7+17]\\2-24\\=-22$

espero ter ajudado!!

;-)