Question

me ajudaaaa!!!!!!
reduza os radicais em um só e calcule

Answer 1

Resposta:

$\frac{\sqrt[2]{16}}{\sqrt[2]{25}}=\frac{4}{5}\\ \\\sqrt[3]{\sqrt[2]{1}} = \sqrt[3]{1} = 1 \\\\\sqrt[2]{150^6}= 150^{\frac{6}{2}} = 150^3 = 3.375.000 \\\\\sqrt[2]{4}.\sqrt[2]{9} = 2.3 = 6$