Question

Me ajudaaaa! Assunto de prova expressão númerica

Answer 1

$\left[ 1+\dfrac{6}{4}\cdot \left( \dfrac{1}{2}-\dfrac{1}{3}\right)\right]:\dfrac{1}{16}=\\\text{Primeiro eliminamos os parenteses...}\\\left[ 1+\dfrac{6}{4}\cdot \left( \dfrac{3-2}{6}\right)\right]:\dfrac{1}{16}=\\\left[ 1+\dfrac{6}{4}\cdot \dfrac{1}{6}\right]:\dfrac{1}{16}=\\\text{Agora resovemos a multiplicacao que surgiu no meio da operacao}\\\left[ 1+\dfrac{6}{24}\right]:\dfrac{1}{16}=\\\text{Simplificamos a fracao obtida para facilitar as operacoes}$

Continuando...

$\left[ 1+\dfrac{6}{24}\right]:\dfrac{1}{16}=\\\left[ 1+\dfrac{1}{4}\right]:\dfrac{1}{16}=\\\text{Eliminando o Colchete}\\\left[ \dfrac{4+1}{4}\right]:\dfrac{1}{16}=\\\dfrac{5}{4}:\dfrac{1}{16}=\\\\\text{Na divisao multiplica a primeira pelo inverso da segunda}\\\dfrac{5}{4}\times \dfrac{16}{1}=\dfrac{5\times 16}{4\times 1}\\=\dfrac{80}{4}\\=20$

Espero ter sido útil