Question

Me ajudaa

(X-5)²= 4

(2x+4)²= 0

Answer 1

Resposta:

(x - 5)^2 = 4

(x - 5)(x - 5) = 4

x^2 - 5x - 5x + 25 = 4

x^2 - 10x + 25 = 4 a=1 b=-10 c=25

Delta=

${b}^{2} - 4ac$

${(10)}^{2} - 4.1.21 \\ 100 - 84 = 16 \\ \sqrt{16} = 4$

Baskara=

$\frac{ - b \binom{ + }{ - } \sqrt{delta} }{2a}$

$x = \frac{ - ( - 10) \binom{ + }{ - } 4}{2.1} = \frac{10 \binom{ + }{ - }4 }{2} \\ {x}^{1} = \frac{10 + 4}{2} = \frac{14}{2} = 7 \\ {x}^{2} = \frac{10 - 4}{2} = \frac{6}{2} = 3$

(2x + 4)^2 = 0

(2x + 4)(2x + 4) = 0

4x^2 + 8x + 8x + 16 = 0

4x^2 + 16x + 16 = 0

a=4 b=16 c=16

Delta=

${b}^{2} - 4ac$

${16}^{2} - 4.4.16 \\ 256 - 256 = 0 \\ \sqrt{0} = 0$

Baskara=

$x = \frac{ - b \binom{ + }{ - } \sqrt{delta} }{2a}$

$x = \frac{ - 16 \binom{ + }{ - } 0}{2.4} = \frac{ - 16 \binom{ + }{ - } 0}{8} = \\ {x}^{1} = \frac{ - 16 + 0}{8} = \frac{ - 16}{8} = - 2 \\ {x}^{2} = \frac{ - 16 - 0}{8} = \frac{ - 16}{8} = - 2$