Matemática, perguntado por anaclaralisbs, 4 meses atrás

ME AJUDA POR FAVOR!!!!!!

a) 4x - 1 = 3(x - 1)
b) 3(x - 2) = 2x - 4
c) 2(x - 1) = 3x + 4
d) 3(x - 1) - 7 = 15
e) 7(x - 4) = 2x - 3
f) 3(x - 2) = 4(3 - x)
g) 3(3x - 1) = 2(3x + 2)
h) 7(x - 2) = 5(x + 3)
i) 2x + 5 - 5x = - 1
j) 5 + 6x = 5x + 2
k) x + 2x - 1 - 3 = x
L) - 3x + 10 = 2x + 8 + 1
m) 5x - 5 + x = 9 + x
n) 7 (x-5)=3(x+1)
o) 3(x - 2) = 4(- x + 3)
p) 2(x + 1) - (x - 1) = 0

Soluções para a tarefa

Respondido por Emerre
2

 a)~-2; ~b)~+2;~c)~-6;~d)~ \dfrac{25}{3};~e)~+5;~f)~+\dfrac{18}{7};~g)~+\dfrac{7}{3} ; ~h)~+\dfrac{29}{2} ;~i)~+2;~j)~-3;~k)~+2;~l)~+\dfrac{1}{5} ;~m)~+\dfrac{14}{5} ;~n)~+\frac{19}{2};~o)~+\dfrac{18}{7},~p)~-3

Equação de primeiro grau.

Como resolver?

Deixaremos todos os elementos que tenham a incógnita "x" de um lado da igualdade e os outros termos, os termos independentes, passarão para o outro lado da igualdade.

Atentar que quando trocam de lado eles invertem os seus sinais, se positivo passa para o outro lado negativo, se negativo passa para o outro lado positivo.

E por último o número que está multiplicando o valor de "x" passa para o outro lado dividindo.

Teremos a resposta de sua equação de primeiro grau.

a) 4x - 1 = 3(x - 1)

4x-1=3x-3\\\\\\4x-3x=-3+1\\\\\\x=-2

b) 3(x - 2) = 2x - 4

3x-6=2x-4\\\\\\3x-2x=-4+6\\\\\\x=+2

c) 2(x - 1) = 3x + 4

2x-2=3x+4\\\\\\2x-3x=+4+2\\\\\\-x=+6\\\\\\multiplicamos~por~menos~1~~.(-1)\\\\para~termos~o~valor~de~x~positivo\\\\\\x=-6

d) 3(x - 1) - 7 = 15

3x-3-7=15\\\\\\3x-10=+15\\\\\\3x=15+10\\\\\\3x=+25\\\\\\x=+\dfrac{25}{3} \\\\

e) 7(x - 4) = 2x - 3

7x-28=2x-3\\\\\\7x-2x=-3+28\\\\\\5x=+25\\\\\\x=+\dfrac{25}{5} \\\\\\simplificando~por~5, ~teremos:\\\\\\x=+5

f) 3(x - 2) = 4(3 - x)

3x-6=12-4x\\\\\\3x+4x=+12+6\\\\\\7x=+18\\\\\\x=+\dfrac{18}{7} \\\\

g) 3(3x - 1) = 2(3x + 2)

9x-3=6x+4\\\\\\9x-6x=+4+3\\\\\\3x=+7\\\\\\x=+\dfrac{7}{3} \\\\

h) 7(x - 2) = 5(x + 3)

7x-14=5x+15\\\\\\7x-5x=+15+14\\\\\\2x=+29\\\\\\x=+\dfrac{29}{2} \\\\

i) 2x + 5 - 5x = - 1

2x-5x=-1-5\\\\\\-3x=-6\\\\\\multilipicar~por~menos~1~~(-1)\\\\3x=+6\\\\\\x=+\dfrac{6}{3} \\\\\\simplificando~por~3\\\\\\x=+2

j) 5 + 6x = 5x + 2

6x-5x=+2-5\\\\\\x=-3

k) x + 2x - 1 - 3 = x

x+2x-x=+4\\\\\\3x-x=+4\\\\\\2x=+4\\\\\\x=+\dfrac{4}{2} \\\\\\simplificamos~por~2\\\\\\x=+2

L) - 3x + 10 = 2x + 8 + 1

-3x-2x=+9-10\\\\\\-5x=-1\\\\\\multiplicamos~por~menos~1~~.(-1)\\\\\\5x=+1\\\\\\x=+\dfrac{1}{5} \\

m) 5x - 5 + x = 9 + x

5x+x-x=+9+5\\\\\\6x-x=+14\\\\\\5x=+14\\\\\\x=+\dfrac{14}{5}\\

n) 7 (x-5)=3(x+1)

7x-35=3x+3\\\\\\7x-3x=+3+35\\\\\\4x=+38\\\\\\x=+\dfrac{38}{4} \\\\\\simplificamos~por~2\\\\\\x=+\dfrac{19}{2} \\

o) 3(x - 2) = 4(- x + 3)

3x-6=-4x+12\\\\\\3x+4x=+12+6\\\\\\+7x=+18\\\\\\x=+\dfrac{18}{7} \\\\

p) 2(x + 1) - (x - 1) = 0

2x+2-x+1=0\\\\\\2x-x+2+1=0\\\\\\x+3=0\\\\\\x=-3

Para saber mais acesse os links abaixo

Equação de primeiro grau

brainly.com.br/tarefa/40277534

brainly.com.br/tarefa/47455627

Anexos:
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