ME AJUDA POR FAVO RAPIDO DA AQUI APOUCO TENHO PROVA
Anexos:
![](https://pt-static.z-dn.net/files/d2b/d152585fb55adbd58aeb409b08b12a88.jpg)
Soluções para a tarefa
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Pode ser calculado como método de regra de três:
![\frac{12}{24} = \frac{x}{9} \\\\ \frac{1}{2} = \frac{x}{9} \\\\2x=9\\x= \frac{9}{2} \frac{12}{24} = \frac{x}{9} \\\\ \frac{1}{2} = \frac{x}{9} \\\\2x=9\\x= \frac{9}{2}](https://tex.z-dn.net/?f=+%5Cfrac%7B12%7D%7B24%7D+%3D+%5Cfrac%7Bx%7D%7B9%7D+%5C%5C%5C%5C+%5Cfrac%7B1%7D%7B2%7D+%3D+%5Cfrac%7Bx%7D%7B9%7D+%5C%5C%5C%5C2x%3D9%5C%5Cx%3D+%5Cfrac%7B9%7D%7B2%7D+)
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![\frac{x}{20} = \frac{15}{3} \\\\ \frac{x}{20}=5\\\\x=20.5\\x=100 \frac{x}{20} = \frac{15}{3} \\\\ \frac{x}{20}=5\\\\x=20.5\\x=100](https://tex.z-dn.net/?f=+%5Cfrac%7Bx%7D%7B20%7D+%3D+%5Cfrac%7B15%7D%7B3%7D+%5C%5C%5C%5C+%5Cfrac%7Bx%7D%7B20%7D%3D5%5C%5C%5C%5Cx%3D20.5%5C%5Cx%3D100+)
![\frac{y}{20} = \frac{32}{3} \\\\3y=640\\y= \frac{640}{3} \frac{y}{20} = \frac{32}{3} \\\\3y=640\\y= \frac{640}{3}](https://tex.z-dn.net/?f=+%5Cfrac%7By%7D%7B20%7D+%3D+%5Cfrac%7B32%7D%7B3%7D+%5C%5C%5C%5C3y%3D640%5C%5Cy%3D+%5Cfrac%7B640%7D%7B3%7D+)
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