Question

me ajuda pf eu presizo pra hoje

Answer 1

.
Ola anilo

BC = 15
AD = 15
DM = 16
KC = 12
AK = 11

BC² = KC² + KB²
15² = 12² + KB²
225 = 144 + KB²
KB² = 225 - 144 = 81
KB = 9

AB = AK + KB = 11 + 9 = 20
DC = 20

DC² = DM²  + MC²
20² = 16² + MC²
MC² = 400 - 256 = 144
MC = 12

a) KB = 9 cm
b) pKBC = 15 + 9 + 12 = 36 cm
c) pABCD = 15 + 15 + 20 + 20 = 70 cm
d) pABMB = 15 + 12 + 16 + 15 + 20 = 78 cm

DB² = AD² + AB²
DB² = √6² + √6² = 6 + 6 = 12
DB = √12 = 2√3

a) lado = 2√3
b) altura = √3lado/2 = √3*2√3/2 = 3

x + 2 + x + x - 2 = 24
3x = 24
x = 8

hipotenusa a = x + 2 = 10
cateto b = x = 8
cateto c = x - 2 = 6

altura relativa
b*c = h*a
6*8 = h*10
h = 48/10 = 4.8

valores de m e n

b² = m*a
64 = m*10
m = 64/10 = 6.4

c² = n*a
36 = n*10
n = 36/10 = 3.6