Matemática, perguntado por islanesantoscunha99, 5 meses atrás

Me ajuda nessa questão


3x-2y=30
2x+3y=90

Soluções para a tarefa

Respondido por attard
1

\LARGE\displaystyle{}\begin{cases}3x - 2y = 30 \\ 2x + 3y = 90\end{cases} \\\\\\ \LARGE\displaystyle{}\begin{cases}x = 10 +  \dfrac{2}{3}y \\ \\  2x + 3y = 90 \end{cases} \\\\\\\LARGE\displaystyle{}2 \left(10 +  \dfrac{2}{3}y \right) + 3y = 90 \\\\\\ \LARGE\displaystyle{}y =  \dfrac{210}{13}  \\\\\\ \LARGE\displaystyle{}x = 10 +  \dfrac{2}{3}  \times  \dfrac{210}{13}  \\\\\\ \LARGE\displaystyle{}x =  \dfrac{270}{13}  \\\\\ \LARGE\displaystyle\text{$\begin{gathered} \underline{\boxed{\boldsymbol{  \left(x,y\right) =\left( \dfrac{270}{13}, \dfrac{210}{13}  \right) }}}\end{gathered}$}

\LARGE\displaystyle\text{$\begin{gathered} \underline{\boxed{\boldsymbol{{ \red{Bons}}  \blue{\:Estudos}}}}\end{gathered}$}

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