Question

me ajuda nessa atividade porfavo ​

Answer 1

Resposta:

Olá bom dia!

Pelas propriedades da potenciação:

$a^n.a^m =a^{n+m}\\\\\frac{a^n}{a^m}=a^n:a^m = a^{n-m}$

Então:

$e)\\A^8.A^{-8}.A^{-1} \\\\= A^{8+(-8)+(-1)} = \\\\=A^{8-8-1}\\\\=A^{8-9}\\\\=A^{-1}\\\\= \frac{1}{A}$

$f)\\6^4.6^5\\\\=6^{4+5}\\\\=6^9$

g)

$\frac{2^7}{2^{-2}} =\\\\=2^{7-(-2)}\\\\= 2^{2+7}\\\\=2^9$

h)

$7^3$

i)

10²

j)

x⁸