Question

Me ajuda com essa resposta, por favor

Answer 1

Resolução:
$\sqrt{x+6} =x$

$(\sqrt{x+6})^2=x^2$

$x^{2} -x-6=0$

$x= \frac{-b+/- \sqrt{b^2-4.a.c} }{2.a}$

$x= \frac{-(-1)+/- \sqrt{(-1)^2-4.1.(-6)} }{2.1}$

$x= \frac{1+/- \sqrt{25} }{2}$

$x= \frac{1+/-5}{2}$

$x`= \frac{1+5}{2} = \frac{6}{2} = 3$

$x``= \frac{1-5}{2} = \frac{-4}{2} =-2$

S = { -2 ; 3}

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