Question

Me ajuda
álgebra
preciso
urgente​

Answer 1

a)

$\sqrt[10]{ {2}^{8} } = \sqrt[x]{ {2}^{4} } \\ {2}^{ \frac{8}{10} } = {2}^{ \frac{4}{x} } \\ 8x = 10 \times 4 \\ 8x = 40 \\ x = \frac{40}{8} \\ x = 5$

b)

$\sqrt[15]{ {3}^{5} } = \sqrt[3]{ {3}^{x} } \\ {3}^{ \frac{5}{15} } = {3}^{ \frac{x}{3} } \\ 5 \times 3 = 15 x \\ 15 = 15x \\ 1 = x$

c)

$\sqrt[8]{ {5}^{4} } = \sqrt{ {5}^{x} } \\ {5}^{ \frac{4}{8} } = {5}^{ \frac{x}{2} } \\ 4 \times 2 = 8x \\ 8 = 8x \\ 1 = x$

d)

$\sqrt[16]{ {4}^{x} } = \sqrt[8]{4} \\ {4}^{ \frac{x}{16} } = {4}^{ \frac{1}{8} } \\ 16 \times 1 = 8x \\ 16 = 8x \\ 2 = x$