Question

Me ajuda a responder to com dúvida

Answer 1

Explicação passo-a-passo:

21- a) O total de vendas dos planos I e II é a soma dos três meses:

         J + F + M

         $\left[\begin{array}{ccc}15&25&22\\23&16&18\\\end{array}\right\left\begin{array}{ccc}19\\21\\\end{array}\right]+\left[\begin{array}{ccc}18&24&22\\20&21&19\\\end{array}\right\left\begin{array}{ccc}25\\23\\\end{array}\right]+\left[\begin{array}{ccc}22&25&20\\22&20&26\\\end{array}\right\left\begin{array}{ccc}23\\19\\\end{array}\right]$

         $\left[\begin{array}{ccc}15+18+22&25+24+25&22+22+20\\23+20+22&16+21+20&18+19+26\\\end{array}\right\left\begin{array}{ccc}19+25+23\\21+23+19\\\end{array}\right]$

         $\left[\begin{array}{ccc}55&74&64\\65&57&63\\\end{array}\right\left\begin{array}{ccc}67\\63\\\end{array}\right]$

   b) Plano I  →  bairro B

       Plano II  →  bairro A

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22- Seja uma matriz A.

      Matriz oposta é a matriz que somada com a matriz A resulta em

      uma matriz nula.

      A oposta da matriz A é a matriz -A.

      Basta simplesmente trocar os sinais da matriz A ou multiplicar

      cada elemento por -1.

   a)

       $A=\left[\begin{array}{ccc}2&1\\5&0\\\end{array}\right]$

       $A=\left[\begin{array}{ccc}2&1\\5&0\\\end{array}\right].(-1)=\left[\begin{array}{ccc}2.(-1)&1.(-1)\\5.(-1)&0.(-1)\\\end{array}\right]=\left[\begin{array}{ccc}-2&-1\\-5&0\\\end{array}\right]$

   ---------------------------------------------------------------------------------------

   b)

       $B=\left[\begin{array}{ccc}1&-\pi\\3&-4\\\end{array}\right]$

       $B=\left[\begin{array}{ccc}1&-\pi\\3&-4\\\end{array}\right].(-1)=\left[\begin{array}{ccc}1.(-1)&-\pi.(-1)\\3.(-1)&-4.(-1)\\\end{array}\right]=\left[\begin{array}{ccc}-1&\pi\\-3&4\\\end{array}\right]$

   ---------------------------------------------------------------------------------------

   c)

       $C=\left[\begin{array}{ccc}1&-0,5&-1\\\sqrt[3]{-6}&2&10\\-3&0&1\end{array}\right]$

        $C=\left[\begin{array}{ccc}1&-0,5&-1\\\sqrt[3]{-6}&2&10\\-3&0&1\end{array}\right].(-1)=\left[\begin{array}{ccc}1.(-1)&-0,5.(-1)&-1.(-1)\\\sqrt[3]{-6}.(-1)&2.(-1)&10.(-1)\\-3.(-1)&0.(-1)&1.(-1)\end{array}\right]=\left[\begin{array}{ccc}-1&0,5&1\\\sqrt[3]{6} &-2&-10\\3&0&-1\end{array}\right]$

   --------------------------------------------------------------------------------------

   d)

       $D=\left[\begin{array}{ccc}1&0&0\\0&-1&0\\0&0&1&-1&1&0\end{array}\right\left\begin{array}{ccc}-1\\1\\0\\-1\end{array}\right]$

       $D=\left[\begin{array}{ccc}1&0&0\\0&-1&0\\0&0&1&-1&1&0\end{array}\right\left\begin{array}{ccc}-1\\1\\0\\-1\end{array}\right].(-1)=\left[\begin{array}{ccc}1.(-1)&0.(-1)&0.(-1)\\0.(-1)&-1.(-1)&0.(-1)\\0.(-1)&0.(-1)&1.(-1)&-1.(-1)&1.(-1)&0.(-1)\end{array}\right\left\begin{array}{ccc}-1.(-1)\\1.(-1)\\0.(-1)\\-1.(-1)\end{array}\right]=\left[\begin{array}{ccc}-1&0&0\\0&1&0\\0&0&-1&1&-1&0\end{array}\right\left\begin{array}{ccc}1\\-1\\0\\1\end{array}\right]$