Question

me ajuda 15pts!!

(2n+1)² + (n+2)² + 2 (n+1)(n-1)

(apresente calculos)
a)7n²+8n+3
b)7n²+6n+3
c)7n²+6n+4
d)7n²+8n+4

Answer 1

$(2n+1)^2 + (2n+2)^2+2(n+1)(n-1)$

Vamos simplificar

$(2n+1)^2 \to (2n+1)*(2n+1) \to 4n^2 + 2n + 2n + 1 \to 4n^2 + 4n +1$

$(n+2)^2 \to (n+2)*(n+2) \to n^2+2n+2n+4 \to n^2+4n+4$

$2(n+1)(n-1) \to (2n+2) *(n-1) \to 2n^2-2n+2n-2$

Agora é só somar

$(4n^2 +n^2 +2n^2) +(4n+4n+2n-2n)+(1+4-2) \to 7n^2+8n+3$