Question

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E) 55-(×√9×√4+1)²+(4²+3²)÷5²+1^6=





F) (√64-8÷2³-(15-5׳√8))+4²=

Answer 1

e)

$\frac{55-\left(\sqrt{9}\sqrt{4}+1\right)^2+\left(4^2+3^2\right)}{5^2+1^6}$

$\frac{55-\left(1+\sqrt{9}\sqrt{4}\right)^2+16+9}{26}$

$\left(\sqrt{9}\sqrt{4}+1\right)^2\\\sqrt{9}\sqrt{4}=6$

$7^2$

$\frac{55-7^2+16+9}{26}\\55-7^2+16+9\\=55-49+16+9\\=31\\=\frac{31}{26}$