Question

(MATRIZES)Qual a solução da equação $\left[\begin{array}{ccc}2&2X\\-1&2&\\&&\end{array}\right]$ = $\left[\begin{array}{ccc}x&-2\\3&-4&\\\end{array}\right]$ + 3
                           

Answer 1

Milena, basta fazer:

$\left|\begin{array}{ccc}~~2&2x\\-1&2\\\end{array}\right| = \left|\begin{array}{ccc}x&-2\\3&-4\\\end{array}\right| +3\\\\\\ 2\cdot2-(-1)\cdot2x=(-4)\cdot x-(-2)\cdot3+3\\ 4+1\cdot 2x=-4x+2\cdot3+3\\ 4+2x=-4x+6+3\\ 4+2x=-4x+9\\ 2x+4x=9-4\\ 6x=5\\\\ x= \dfrac{5}{6}\\\\\\ \Large\boxed{\boxed{S=\left\{ \dfrac{5}{6}\right\}}}.\\.$

Tenha ótimos estudos ;D