Matriz:
De a matriz A=(aij)4×3, em que:
aij={0,se i ≥ j
1, se i < j
Soluções para a tarefa
Respondido por
19
Olá Luiza.
![A= \left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\a_{31}&a_{32}&a_{33}\\ a_{41}&a_{42}&a_{43}\end{array}\right] \\ \\ \\ A=\left[\begin{array}{ccc}0&1&1\\0&0&1\\0&0&0\\0&0&0\end{array}\right]](https://tex.z-dn.net/?f=A%3D+%C2%A0%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da_%7B11%7D%26amp%3Ba_%7B12%7D%26amp%3Ba_%7B13%7D%5C%5Ca_%7B21%7D%26amp%3Ba_%7B22%7D%26amp%3Ba_%7B23%7D%5C%5Ca_%7B31%7D%26amp%3Ba_%7B32%7D%26amp%3Ba_%7B33%7D%5C%5C+a_%7B41%7D%26amp%3Ba_%7B42%7D%26amp%3Ba_%7B43%7D%5Cend%7Barray%7D%5Cright%5D+%5C%5C+%5C%5C+%5C%5C+A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%26amp%3B1%26amp%3B1%5C%5C0%26amp%3B0%26amp%3B1%5C%5C0%26amp%3B0%26amp%3B0%5C%5C0%26amp%3B0%26amp%3B0%5Cend%7Barray%7D%5Cright%5D+ "A= \left[\begin{array}{ccc}a_{11}&a_{12}&a_{13}\\a_{21}&a_{22}&a_{23}\\a_{31}&a_{32}&a_{33}\\ a_{41}&a_{42}&a_{43}\end{array}\right] \\ \\ \\ A=\left[\begin{array}{ccc}0&1&1\\0&0&1\\0&0&0\\0&0&0\end{array}\right]")
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6
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