Question

MATEMATICA AJUDA PFVRR
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Answer 1

Resposta:

Alternativa B

Explicação passo-a-passo:

$1,3=\boxed{\dfrac{13}{10}}$

$1,333333333333....=1+0,333333333333=1+\dfrac{3}{9} =1+\dfrac{1}{3}=\dfrac{3+1}{3} =\boxed{\dfrac{4}{3}}$

$\dfrac{2+\sqrt{(-3)^2} }{15} =\dfrac{2+\sqrt{9} }{15}=\dfrac{2+3 }{15}=\dfrac{5}{15} =\boxed{\dfrac{1}{3}}$

Substituindo agoraaaa k k k :

$\dfrac{13}{10} -\dfrac{4}{3} +\dfrac{1}{3} =\dfrac{13}{10}-\dfrac{3}{3}=\dfrac{13}{10} -1=\dfrac{13-10}{10}=\boxed{\boxed{\dfrac{3}{10}}}$