mais uma de log

A resposta é -13/2 , já tentei usando as propriedades mas não obtive sucesso , alguém disposto ?
Soluções para a tarefa
Respondido por
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Começando por log(1/2) 32:



Agora log 0,001:





Depois,





Por fim:



Agora log 0,001:
Depois,
Por fim:
sotaj304:
eu errei alguma coisa...
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