Matemática, perguntado por 313245, 4 meses atrás

M.M.C 4,6,9,15




ME AJUDAAAAAAAAA​

Soluções para a tarefa

Respondido por Math739
3

\begin{array}{c|c}\sf4~~6~~9~~15&\sf2\\\sf2~~3~~9~~15&\sf2\\\sf1~~3~~9~~15&\sf3\\\sf1~~1~~3~~5&\sf3\\\sf1~~1~~1~~5&\sf5\\\sf1~~1~~1~~1\end{array}

\sf m\cdot m\cdot c(4,6,9,15)=2^2\cdot3^2\cdot5

\boxed{\boxed{\sf m\cdot m\cdot c(4,6,9,15)=180}}

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