Question

m d) 3(x2 - y2) - 10(x + y) - (x - y), quando x = -2 e y = -2.​

Answer 1

$= 3(x {}^{2} - y {}^{2} ) - 10(x + y) - (x - y)$

$\boxed{x = - 2 \: \: e \: \: y = - 2}$

$= 3( ( - 2) {}^{2} - ( ( - 2) {}^{2} ) - 10( - 2 + ( - 2)) - ( - 2 - ( - 2))$

$= 3 \: . \: 0 - 10( - 2 - 2) - ( - 2 + 2)$

$= 0 - 10( - 2 - 2) - ( - 2 + 2)$

$= 0 - 10 \: . \: ( - 4) - 0$

$= - 10 \: . \: ( - 4)$

$= 10 \: . \: 4$

$\boxed{ = 40}$

Att. NLE Top Shotta