Question

(m-2)(9-m)+8=3(m-1)(m-2) resposta e cálculos

Answer 1

$(m-2)(9-m)+8=3(m-1)(m-2)\\ 9m-m^2-18+2m+8=3(m^2-2m-m+2)\\ 9m-m^2-18+2m+8=3m^2-6m-3m+6\\ 9m-m^2-18+2m+8-3m^2+6m+3m-6\\ -4m^2+20m-16=0\\ \\ \Delta=20^2-4.(-4).(-16)=144\\ \\ x=\frac{-20\pm 12}{-8}\\ \\ x_1=1\\ \\ x_2=4$