Question

Logx10, sendo logx2=3 e logx5=4​

Answer 1

Resposta:

$\boxed{\mathtt{Sete}}$

Explicação passo a passo:

Olá!

$\displaystyle \mathtt{\log_x 10 =} \\\\ \mathtt{\log_x ( 2 \cdot 5 )} \\\\ \mathtt{\log_x 2 + \log_x 5 =} \\\\ \mathtt{3 + 4 =} \\\\ \boxed{\boxed{\mathtt{7}}}$

Propriedade utilizada:

$\boxed{\mathbf{\log_a ( b \cdot c ) = \log_a b + \log_a c}} \ \mathbf{onde \ 0 < a \neq 1, \forall \ b, c > 0}$