Question

logx=log25+colog5+log2

Answer 1

$colog~a=-log~a$
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$log~x=log~25+colog~5+log~2\\log~x=log~25-log~5+log~2\\log~x=log~(25\cdot2/5)\\log~x=log~(5\cdot2)\\log~x=log~10\\\\\boxed{\boxed{x=10}}$