Question

logaritimossss me ajudeee valendo 40 pontos

Answer 1

R: Letra D
veja

$\log_{10} { ( x^{2} -6x+10)$

$f(6)=\log_{10} {6^2-6(6)+10$

$f(6)=log_{10} {36-36+10$

$f(6)=\log_{10 } {10}$


$f(-2)=\log_{10} {(-2)^2-6(-2)+10$

$f(-2)=\log_{10} {4+12+10$

$f(-2)=\log_{10} {26}$

Logo

$\log_{10} {10}-\log_{10} {26}=\log_{10}{ \frac{10}{26} =\log_{10} { \frac{5}{13} }$

Answer 2

Dadas a função :

$\boxed{f(x)=\log{(x^2-6x+10)}}$

Calcular: $f(6)-f(-2)$

$f(6)=\log{(6^2-6*6+10)}\\ \\f(6)=\log{10}$

$f(-2)=\log{((-2)^2-6*(-2)+10)}\\ \\f(-2)=\log{26}$

Calculando a diferença:

$\log{10}-\log{26}=\log( \frac{10}{26} )~\to~\boxed{\therefore~\log {\frac{5}{13}} }$

Alternativa D