Question

(loga)²- (logb)=log(ab)
Como resolver?

Answer 1

2loga - logb= logab
2loga - logb = loga (logb)
-logb = loga .(logb) + 2 loga

-logb = loga(logb)  + 2 loga. (-1)
logb = - loga . logb - 2loga 
cancela-se logb com logb
e ifgaca 
-loga . (-2loga)

-loga . (-2loga) . -(1)
loga. 2loga
log= 2loga/ loga
log= logx
log=logA