Question

Log7 (x2-5x+5)=0 qual a resposta?

Answer 1

$\LARGE\tt{} log_{7}(x \times 2 - 5x) = 0 \\\LARGE\tt{}x \times 2 - 5x + 5 = 0 \\\LARGE\tt{}2x - 5x + 5 = 0 \\ \LARGE\tt{} - 3x + 5 = 0 \\ \LARGE\tt{} - 3x = - 5 \\ \LARGE\tt{} \LARGE\tt{}x = \dfrac{5}{3}$

bons estudos

Answer 2

Resposta:

S={1,4}

Explicação passo-a-passo:

Resolução :

x² - 5x + 5 =7°

X² - 5x +5 - 1 =0

X² - 5x +4 = 0

Δ=(-5)² - 4.1.4

Δ=25 - 16

Δ=9

x= 5±3

____

2

x'= 8

__ = 4

2

x" = 2

__= 1

2

S={1,4}