Question

log5 (1-x) + log 5 (2x)=log5 8-2x

Answer 1

$\log_5 (1-x) + \log _5 (2x)=log_5 (8-2x)\\\\\log_5 (2x(1-x))=log_5 (8-2x)\\\\2x(1-x)=8-2x\\\\2x-2x^2=8-2x\\\\2x^2-4x+8=0\\\\x=1\pm i\sqrt3$