Question

log4 x^2+3x-1=log4 5x-1

Answer 1

$log_{4}x^{2}+3x+1 = log_{4}5x + 1 \\ \\ x^{2} + 3x + 1 = 5x + 1 \\ \\ x^{2}+3x-5x-1+1=0 \\ \\ x^{2}-2x=0 \\ \\ x(x-2)=0 \\ \\ x=0 \\ x-2 = 0 -\ \textgreater \ x = 2$

Resposta: x = 0 ou x = 2

Espero ter ajudado.