Question

log4 (6x-7/3) = log4 (2x-1/4)

Answer 1

$log_{4}( 6x- \frac{7}{3} ) = log_{4}(2x- \frac{1}{4})\\\\6x- \frac{7}{3} =2x- \frac{1}{4}\\\\4x= \frac{7}{3} - \frac{1}{4}\\\\4x= \frac{28-3}{12}\\\\4x= \frac{25}{12}\\\\x= \frac{25}{48}$