(Log3 x)² - 2log 3 x=3
Sendo que o 3 que acompanha o log é base.
Soluções para a tarefa
Respondido por
1
log^2(3x)-2log(3x)-3=0
(log(3x)-3).(log(3x)+1)=0
log(3x)-3=0
log(3x)+1=0
log(3x)=3,-1
(log(3x)-3).(log(3x)+1)=0
log(3x)-3=0
log(3x)+1=0
log(3x)=3,-1
Respondido por
4
Oi Roberta,
consideremos log_3 x = k, então:

- quando k = - 1:

- quando k = 3:
consideremos log_3 x = k, então:
- quando k = - 1:
- quando k = 3:
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