log3 (logx 27) = 1
resolver
kjmaneiro:
log3 (3 é a base?)
sim
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![\log_3(\log_x27)=1 \\ \\ \log_x27=3^1 \\ \\ \log_x27=3 \\ \\ x^3=27 \\ \\ x=\sqrt[3]{27} \\ \\ x= \sqrt[3]{3^3} \\ \\ x=3](https://tex.z-dn.net/?f=%5Clog_3%28%5Clog_x27%29%3D1+%5C%5C++%5C%5C+%5Clog_x27%3D3%5E1+%5C%5C++%5C%5C+%5Clog_x27%3D3+%5C%5C++%5C%5C+x%5E3%3D27+%5C%5C++%5C%5C++x%3D%5Csqrt%5B3%5D%7B27%7D++%5C%5C++%5C%5C+x%3D+%5Csqrt%5B3%5D%7B3%5E3%7D++%5C%5C++%5C%5C+x%3D3 "\log_3(\log_x27)=1 \\ \\ \log_x27=3^1 \\ \\ \log_x27=3 \\ \\ x^3=27 \\ \\ x=\sqrt[3]{27} \\ \\ x= \sqrt[3]{3^3} \\ \\ x=3")
OKK!!!
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