Question

log3 3 + log2 1/2 +log5 √5.

Answer 1

Explicação passo-a-passo:

Temos que:

$\bullet~~\text{log}_{3}~3=1$

$\bullet~~\text{log}_{2}~\dfrac{1}{2}=\text{log}_{2}~2^{-1}=-1$

$\bullet~~\text{log}_{5}~\sqrt{5}=\text{log}_{5}~5^{\frac{1}{2}}=\dfrac{1}{2}$

Assim:

$\text{log}_{3}~3+\text{log}_{2}~\dfrac{1}{2}+\text{log}_{5}~\sqrt{5}=1-1+\dfrac{1}{2}$

$\text{log}_{3}~3+\text{log}_{2}~\dfrac{1}{2}+\text{log}_{5}~\sqrt{5}=\dfrac{1}{2}$

Answer 2

Oie, Td Bom?!

$log_{3}3 + log_{2} \frac{1}{2} + log_{5} \sqrt{5}$

$1 + log_{2}2 {}^{ - 1} + log_{5}5 {}^{ \frac{1}{2} }$

$1 - 1 + \frac{1}{2} = \frac{1}{2}$

Att. Makaveli1996