Question

Log27 [2+log5 (x^2-11)]= 1/3

Answer 1

Oi

Resolvendo usando as propriedades de logaritmo ...

log 27 [2 + log5 (x^2-11)] = 1/3

27^1/3 = 2 + log5 (x²-11)

∛27 = 2 + log5 (x²-11)

3 = 2 + log5 (x²-11)

3 - 2 = log5 (x²-11)

1 = log5 (x²-11)

5^1 = x² - 11

5 = x² - 11

5 + 11 = x²

x² = 16

x = √16

x' = 4

x'' = - 4                       S = { -4 , 4 }

Bons estudos! :)