Question

Log25base5+log8base8+log81base9-log16base2

Answer 1

Resposta:

1

Explicação passo-a-passo:

$log_{5}^{25} + log_{8}^{8} + log_{9}^{81} - log_{2}^{16}$

$log_{5}^{5^{2}} + log_{8}^{8} + log_{9}^{9^{2}} - log_{2}^{2^{4}}$

* Lembrar que:

$log_{a}^{a} = 1$

$log_{a}^{a^{b}} = b$

Logo:

$log_{5}^{5^{2}} + log_{8}^{8} + log_{9}^{9^{2}} - log_{2}^{2^{4}}$

2 + 1 + 2 - 4

5 - 4 = 1